Could you possibly explain the effect of inhibitors on the V vs. S curve in relation to the Michealis-Menten equation; ie, what terms in the equation are changing to have the corresponding effect on the graph?
The inhibitors are not changing the Michaelis Menten equation, since that equation can still describe the response of Vo to [S]. That is, the shape of the curve agrees with the form of the equation. But in the presence of the inhibitors, it is AS IF one or the other of the constants has changed. Thus we get an apparent Km that is larger than normal in the presence of a competitive inhibitor. Let's call it Km', so in this condition, Vo=k3Eo[S]/(Km'+[S]). Similarly, in the presence of a non-competitive inhibitor, we can describe the curve by considering the amount of enzyme decreased, subtracting those enzymemolecules that are bound to the inhibitor at any given moment, so we have a new apparent Eo, let's say Eo', that is less than the original Eo, so we can still write Vo= k3Eo'[S]/(Km+[S]) for this condition and generate a curve that agrees with experimental data.